Distance from Lisakovsk to San Jose
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Lisakovsk (SVX) and San Jose (SJC) is 6,235.63 mi (10,035.27 km). This corresponds to an approximate flight time of 12h 18min. Similar flight routes: SVX → OAK , SVX → SFO , SVX → SMF , SVX → RNO , UFA → SJC
Bearing: 97.03° (E)The initial bearing on the course from Lisakovsk to San Jose is 97.03° and the compass direction is E.
Midpoint: 82.1031,-135.78192The geographic midpoint between Lisakovsk and San Jose is in 3,110.79 mi (5,006.32 km) distance between both points in a bearing of 97.03°.
Distance: 6,221.57 mi (10,012.65 km)The shortest distance (air line) between Lisakovsk and San Jose is 6,221.57 mi (10,012.65 km).
Driving route: -- ( - )The shortest route between Lisakovsk and San Jose is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -12hThe time difference between Lisakovsk (Asia/Qostanay) and San Jose (America/Los_Angeles) is -12 hours. This means that it is now 13:26 (14.06.2024) in Lisakovsk and 01:26 (14.06.2024) in San Jose.
How is the distance calculated?
To calculate the distance between Lisakovsk and San Jose, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
San Jose is just as far away from Lisakovsk as Lisakovsk from Los Angeles (10,387 km), Durban (9,658 km), Phoenix (10,440 km), Dallas (10,318 km), Port Elizabeth (10,261 km), Jacksonville (10,165 km), San Francisco (9,962 km), Fort Worth (10,334 km), Charlotte (9,630 km).
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